Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
[tex]n(A)=14[/tex]
[tex]n(B)=11[/tex]
[tex]n(A\cup B)=20[/tex]
We know that,
[tex]n(A\cup B)=n(A)+n(B)-n(A\cap B)[/tex]
[tex]20=14+11-n(A\cap B)[/tex]
[tex]20=25-n(A\cap B)[/tex]
Subtract both sides by 25.
[tex]20-25=-n(A\cap B)[/tex]
[tex]-5=-n(A\cap B)[/tex]
[tex]5=n(A\cap B)[/tex]
We need to find the number of people who have a school certificate only, i.e. [tex]n(A\cap B')[/tex].
[tex]n(A\cap B')=n(A)-n(A\cap B)[/tex]
[tex]n(A\cap B')=14-5[/tex]
[tex]n(A\cap B')=9[/tex]
Therefore, 9 people have a school certificate only.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
