Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Given:
Either has a school certificate or diploma or even both = 20 people
Having school certificates = 14
Having diplomas = 11
To find:
The number of people who have a school certificate only.
Solution:
Let A be the set of people who have school certificates and B be the set of people who have diplomas.
According to the given information, we have
[tex]n(A)=14[/tex]
[tex]n(B)=11[/tex]
[tex]n(A\cup B)=20[/tex]
We know that,
[tex]n(A\cup B)=n(A)+n(B)-n(A\cap B)[/tex]
[tex]20=14+11-n(A\cap B)[/tex]
[tex]20=25-n(A\cap B)[/tex]
Subtract both sides by 25.
[tex]20-25=-n(A\cap B)[/tex]
[tex]-5=-n(A\cap B)[/tex]
[tex]5=n(A\cap B)[/tex]
We need to find the number of people who have a school certificate only, i.e. [tex]n(A\cap B')[/tex].
[tex]n(A\cap B')=n(A)-n(A\cap B)[/tex]
[tex]n(A\cap B')=14-5[/tex]
[tex]n(A\cap B')=9[/tex]
Therefore, 9 people have a school certificate only.
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.