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Calcula la cantidad de calor que hay que darle a 0,01 l de mercurio para que su temperatura pase de 10 ºC a 25 ºC. Datos: rho=13,6 g/cm3 ; Ar(Hg)=200,6; C=28,1 J/(mol∙K).

Sagot :

dsdrajlin

Respuesta:

286 J

Explicación:

Paso 1: Convertir 0,01 L de Hg a cm³

Usaremos los siguientes factores de conversion.

1 L = 1000 mL

1 mL = 1 cm³

0,01 L × 1000 mL/1 L × 1 cm³/1 mL = 10 cm³

Paso 2: Calcular la masa (m) correspondiente a 10 cm³ de Hg

La densidad de Hg es 13,6 g/cm³.

10 cm³ × 13,6 g/cm³ = 136 g

Paso 3: Calcular los moles(n) correspondientes a 136 g de Hg

La masa molar de Hg es 200,6 g/mol.

136 g × 1 mol/200,6 g = 0,678 mol

Paso 4: Calcular la cantidad de calor requerido (Q)

Usaremos la siguiente fórmula.

Q = c × n × (T₂ - T₁)

donde,

c: calor específico del Hg (28,1 J/mol.K = 28,1 J/mol.K)

T₂ y T₁: temperaturas final e inicial, respectivamente

Q = (28,1 J/mol.°C) × 0,678 mol × (25°C - 10 °C) = 286 J

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