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Sagot :
Respuesta:
286 J
Explicación:
Paso 1: Convertir 0,01 L de Hg a cm³
Usaremos los siguientes factores de conversion.
1 L = 1000 mL
1 mL = 1 cm³
0,01 L × 1000 mL/1 L × 1 cm³/1 mL = 10 cm³
Paso 2: Calcular la masa (m) correspondiente a 10 cm³ de Hg
La densidad de Hg es 13,6 g/cm³.
10 cm³ × 13,6 g/cm³ = 136 g
Paso 3: Calcular los moles(n) correspondientes a 136 g de Hg
La masa molar de Hg es 200,6 g/mol.
136 g × 1 mol/200,6 g = 0,678 mol
Paso 4: Calcular la cantidad de calor requerido (Q)
Usaremos la siguiente fórmula.
Q = c × n × (T₂ - T₁)
donde,
c: calor específico del Hg (28,1 J/mol.K = 28,1 J/mol.K)
T₂ y T₁: temperaturas final e inicial, respectivamente
Q = (28,1 J/mol.°C) × 0,678 mol × (25°C - 10 °C) = 286 J
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