Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

the sum of 2 numbers is 56.twice the smaller number exceeds one-half the larger number by 22.find the numbers

Sagot :

sqdancefan

9514 1404 393Answer:

  20, 36

Step-by-step explanation:

Let x and y represent the smaller and larger numbers, respectively. The given relations let us write two equations:

  x + y = 56 . . . . . . the sum of the two numbers is 56

  2x -y/2 = 22 . . . . twice the smaller exceeds half the larger by 22

We can solve this by multiplying the second equation by 2 and adding the first.

  2(2x -y/2) +(x +y) = 2(22) +56

  5x = 100 . . . . . . simplify

  x = 20

  y = 56 -20 = 36

The two numbers are 20 and 36.

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.