Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Consider the system of quadratic equations
y = 3x^2 - 5x,
y = 2x^2 - x - c,
where c is a real number.

(a) For what value(s) of c will the system have exactly one solution (x,y)?

(b) For what value(s) of c will the system have more than one real solution?

(c) For what value(s) of c will the system have no real solutions?

Solutions to the quadratics are (x,y) pairs. Your answers will be in terms of c, but make sure you address both x and y for each part.

Sagot :

sqdancefan

9514 1404 393

Answer:

  (a)  c = 4

  (b)  c < 4

  (c)  c > 4

Step-by-step explanation:

(a) The solutions to the system of equations can be found by substituting one expression for y into the other equation:

  3x^2 -5x = 2x^2 -x -c

  x^2 -4x +c = 0 . . . . . . . subtract the right side expression

The discriminant is

  d = b^2-4ac = (4)^2 -4(1)(c) = 16-4c.

The system will have exactly one solution when d = 0.

  16 -4c = 0

  4 -c = 0

__

(b) There will be more than one real solution when d > 0

  4 -c > 0

  c < 4 . . . . two real solutions

__

(c) There will be no real solutions when d < 0.

  4 -c < 0

  c > 4 . . . . no real solutions

_____

Additional comment

The question posed here simply asks for a value of c. It does not ask for the solutions (x, y). We can count them without knowing exactly what they are.

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.