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help, please
Taylor emptied out her change jar to buy a new soccer ball for practice. The jar contained 128 coins consisting of quarters and dimes that totaled $25.10. Which system of equations could be used to determine how many quarters, q, and how many dimes, d, Taylor had in her change jar?

Sagot :

Answer:

.25q+.10d=25.10

q+d=128

Step-by-step explanation:

Since a quarter is 25 cents and a dime is 10 cents that is how you figure out your first equation. You set it equal to 25.10 because that is the amount of money it totals to. The second equation (q+d=128) is used because the amount of quarters plus dimes needs to make 128.

763396
Let q be the no. of quarters and d be the no. of dimes.

q+d=128
25q+10d=2510

These are the system of equations. To solve it, we do this:

q=128-d
25(128-d)+10d=2510
3200-25d+10d=2510
15d=690
d=46
q=128-46=82
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