Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A cylindrical pipe is 25 ft long and has a volume of 900ft3 find it's approximate diameter to the nearest hundredth of a foot

Sagot :

Answer:

Diameter of the pipe ≈ 6.77 ft

Step-by-step explanation:

Volume of a cylinder = πr²h

Here, r = Radius of the cylindrical pipe

h = Length of the pipe

Volume of the pipe = 900 ft³

Length of the pipe = 25 ft

By substituting the given values in the formula,

900 = π(r)²(25)

r² = [tex]\frac{900}{25\pi}[/tex]

r = √11.459

r = 3.385

Diameter = 2(radius)

                = 2(3.385)

                = 6.77 ft

abidemiokin

The diameter of the cylinderi is 6.77ft

Volume of a cylinder

the formula for calculating thevolume of a cylinder is given as

V = pi d²/4 × h

Given the following

V = 900ft³

h = 25ft

Substitute the given parameters

900 = 3.14 × d²/4 × 25

900 = 19.625d²

d² = 45.859

d = 6.77ft

Hence the diameter of the cylinderi is 6.77ft

learn more on cylinder here: https://brainly.com/question/23935577

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.