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A cylindrical pipe is 25 ft long and has a volume of 900ft3 find it's approximate diameter to the nearest hundredth of a foot

Sagot :

Answer:

Diameter of the pipe ≈ 6.77 ft

Step-by-step explanation:

Volume of a cylinder = πr²h

Here, r = Radius of the cylindrical pipe

h = Length of the pipe

Volume of the pipe = 900 ft³

Length of the pipe = 25 ft

By substituting the given values in the formula,

900 = π(r)²(25)

r² = [tex]\frac{900}{25\pi}[/tex]

r = √11.459

r = 3.385

Diameter = 2(radius)

                = 2(3.385)

                = 6.77 ft

The diameter of the cylinderi is 6.77ft

Volume of a cylinder

the formula for calculating thevolume of a cylinder is given as

V = pi d²/4 × h

Given the following

V = 900ft³

h = 25ft

Substitute the given parameters

900 = 3.14 × d²/4 × 25

900 = 19.625d²

d² = 45.859

d = 6.77ft

Hence the diameter of the cylinderi is 6.77ft

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