Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Following are the responses to the given question.
Step-by-step explanation:
In this question, the points values are missing which is why its solution can be defined as follows:
Let
[tex]l= (7,-1) \\\\m=(-2, 4)\\\\n =(6,5)\\\\[/tex]
Formula:
[tex]d=\sqrt{((x_2-x_1)^2+(y_2-y_1)^2)}[/tex]
For d1:
[tex]x_1=7, y_1=-1, x_2=-2, y_2=4\\\\[/tex]
[tex]d=\sqrt{((-2-7)^2+(4+1)^2)}[/tex]
[tex]=\sqrt{((-2-7)^2+(4+1)^2)}\\\\=\sqrt{((-9)^2+(5)^2)}\\\\=\sqrt{(81+25)}\\\\=\sqrt{(106)}\\\\=10.29[/tex]
For d2:
[tex]x_1=7, y_1=-1, x_2=6, y_2=5\\\\[/tex]
[tex]d=\sqrt{((6-7)^2+(5+1)^2)}[/tex]
[tex]=\sqrt{((-1)^2+(6)^2)}\\\\=\sqrt{(1+36)}\\\\=\sqrt{(37)}\\\\=6.08[/tex]
The first distance value is greater than the second distance value.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
