Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
4.71 minutes
Step-by-step explanation:
Incomplete question [See comment for complete question]
Given
Shape: Cone
[tex]r = 3[/tex] -- radius
[tex]h = 7[/tex] --- height
[tex]Rate = 14in^3/min[/tex]
Required
Time to pass out all liquid
First, calculate the volume of the cone.
This is calculated as:
[tex]V = \frac{1}{3} \pi r^2h[/tex]
This gives:
[tex]V = \frac{1}{3} * 3.14 * 3^2 * 7[/tex]
[tex]V = \frac{1}{3} * 197.82[/tex]
[tex]V = 65.94in^3[/tex]
To calculate the time, we make use of the following rate formula.
[tex]Rate = \frac{Volume}{Time}[/tex]
Make Time the subject
[tex]Time= \frac{Volume}{Rate }[/tex]
This gives:
[tex]Time= \frac{65.94in^3}{14in^3/min}[/tex]
[tex]Time= \frac{65.94in^3}{14in^3}min[/tex]
Cancel out the units
[tex]Time= \frac{65.94}{14} min[/tex]
[tex]Time= 4.71 min\\[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.