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Sagot :
Answer:
[tex]P(Joe) = 0.3[/tex]
[tex]P(Joe\ \&\ North\ Side) = 0.2[/tex]
Explanation:
Solving (a): P(Joe)
To get this probability, we simply add up the items in the column named Joe.
These items are:
Joe: 34 and 70
And the total is:
[tex]Joe = 34 + 70[/tex]
[tex]Joe = 104[/tex]
The overall population of the system is:
[tex]Total = 409[/tex]
So:
[tex]P(Joe) = \frac{Joe}{Total}[/tex]
[tex]P(Joe) = \frac{104}{409}[/tex]
[tex]P(Joe) = 0.3[/tex]
Solving (a): P(Joe and North Side)
To get this probability, we simply get the intersecting element of Joe column and North Side row.
From the table, the intersecting element is:
Joe and North Side: 70
The overall population of the system is:
[tex]Total = 409[/tex]
[tex]P(Joe\ \&\ North\ Side) = \frac{Joe\ \&\ North\ Side}{Total}[/tex]
[tex]P(Joe\ \&\ North\ Side) = \frac{70}{409}[/tex]
[tex]P(Joe\ \&\ North\ Side) = 0.2[/tex]
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