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When determining the amount of an oxidant present by titration, you can use iodine and starch as an indicator.
First, the oxidant, like hypochlorite, oxidizes
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neutral iodine into iodide ion
iodide ion into neutral iodine
iodate polyatomic ion into iodide ion
When starch and iodine are both present, the solution is
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blue-black
brownish yellow
clear
During the titration, the titrant, like thiosulfate, reduces the
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iodide ion into iodate polyatomic ion
neutral iodine into iodide ion
iodide ion into neutral iodine
When the iodine has completely reacted at the endpoint of the titration, the solution should become
Choose...
clear
blue-black
brownish yellow

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Answer:

1. iodide ion into neutral iodine

2. blue-black

3. neutral iodine into iodide ion

4. clear

Explanation:

The function of hypochlorite in iodine titration is to oxidize the iodide ion into iodine molecule as shown below;

ClO-(aq) + 2H+(aq) + 2I-(aq) ---------> 6 I2(l) + Cl- (aq)+ H2O(l)

The addition of starch to iodine leads to the formation of a starch iodide complex which has a blue black colour.

the titrant, thiosulfate, reduces neutral iodine into iodide ion as shown below;

I2  +  2S2O32-  → 2I- + S4O62-

At end point, the solution becomes clear again.

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