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If f(x)=2x^2+x-3, which equation can be used to determine the zeros of the function?
A) 0=(2x-3)(x+1)
B) 0=(2x+3)(x-1)
C) 0=2x(x+1)-3
D) 0=2x(x-1)-3(x+1)​

Sagot :

Answer:

B) 0=(2x+3)(x-1)

Step-by-step explanation:

factor the equation f(x) = 2x² + x - 3

=> f(x) = (2x + 3)(x - 1)

Option B is correct.

What is zeros of a function?

A zero of a function is a member of x of the domain of f such that f(x) vanishes at x, that is the function f attains the value of 0 at x.

According to the given question

we have a function

[tex]f(x)=2x^{2} +x-3[/tex]

[tex]f(x)=2x^{2} + 3x-2x-3[/tex]

[tex]f(x)=2x^{2} -2x+3x-3[/tex]

[tex]f(x)=2x(x-1)+3(x-1)[/tex]

[tex]f(x)=(2x+3)(x-1)[/tex]

for finding the zeros of f(x), substitute f(x)=0

[tex](2x+3)(x-1)=0\\[/tex]

⇒ x=[tex]\frac{-3}{2}[/tex] and x=1

Hence, option B is used for finding the zeros of the given function f(x).

Learn more about the zeros of function here:

https://brainly.com/question/944636

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