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Limestone has a density of 2.72 g/cm3. What is the mass of 8.92 cm3 of limestone?

Sagot :

eeellaaa
it should be 24.2624 because if there’s 2.72g in every cm3 and there are 8.92 cm3, then you simply multiply the two numbers
hope this helped :)
Sarah06109

Answer:

[tex]\boxed {\boxed {\sf 24.2624 \ g}}}[/tex]

Explanation:

Density measures mass per volume. The volume is

[tex]\rho=\frac{m}{v}[/tex]

The density of limestone is 2.72 grams per cubic centimeter. We have a piece of limestone with a volume of 8.92 cubic centimeters.

  • ρ= 2.72 g/cm³
  • v= 8.92 cm₃

Substitute the values into the formula.

[tex]2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}[/tex]

Now we solve for m, the mass, by isolating the variable.

m is being divided by 8.92 cubic centimeters. The inverse of division is multiplication, so we multiply both sides by 8.92 cubic centimeters.

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=\frac{m}{8.92 \ cm^3}* 8.92 \ cm^2[/tex]

[tex]8.92 \ cm^3 * 2.72 \ g/cm^3=m[/tex]

The units of cubic centimeters cancel out.

[tex]24.2624 \ g =m[/tex]

The mass of this piece of limestone is 24.2624 grams.

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