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Sagot :
Since there’s 6 marbles and there’s 3 greens and 2 reds, we’re finding P(A and B). Where P(A) is first marble picked is green, and P(B) is second marble picked is red.
P(A) = 3/6
(Because the first marble as already been picked there’s 5 marbles left) so:
P(B) = 2/5
Now we have to find the probability of A and B
P(A and B) = 3/6 • 2/5 = 1/5 = 20%
P(A) = 3/6
(Because the first marble as already been picked there’s 5 marbles left) so:
P(B) = 2/5
Now we have to find the probability of A and B
P(A and B) = 3/6 • 2/5 = 1/5 = 20%
Answer:
20%
Step-by-step explanation:
3 green, 1 brown, 2 red
3 + 1 + 2 = 6
Total: 6
The probability of picking a green one is 3/6 or 1/2.
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2 green, 1 brown, 2 red
2 + 1 + 2 = 5
New total: 5
The probability of picking a red one is now 2/5.
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First, we multiply them by each other.
2/5 x 1/2 = 1/5
Next, we convert 1/5 to a percentage to get our final answer.
1/5 x 20 = 20/100, which is 20%.
So our final answer is 20%.
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