Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Since there’s 6 marbles and there’s 3 greens and 2 reds, we’re finding P(A and B). Where P(A) is first marble picked is green, and P(B) is second marble picked is red.
P(A) = 3/6
(Because the first marble as already been picked there’s 5 marbles left) so:
P(B) = 2/5
Now we have to find the probability of A and B
P(A and B) = 3/6 • 2/5 = 1/5 = 20%
P(A) = 3/6
(Because the first marble as already been picked there’s 5 marbles left) so:
P(B) = 2/5
Now we have to find the probability of A and B
P(A and B) = 3/6 • 2/5 = 1/5 = 20%
Answer:
20%
Step-by-step explanation:
3 green, 1 brown, 2 red
3 + 1 + 2 = 6
Total: 6
The probability of picking a green one is 3/6 or 1/2.
———————————————————————
2 green, 1 brown, 2 red
2 + 1 + 2 = 5
New total: 5
The probability of picking a red one is now 2/5.
———————————————————————
First, we multiply them by each other.
2/5 x 1/2 = 1/5
Next, we convert 1/5 to a percentage to get our final answer.
1/5 x 20 = 20/100, which is 20%.
So our final answer is 20%.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.