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Sagot :
energy stored in the capacitor= 9.72 x 10⁻⁴ j
explanation:
the energy stored in the capacitor is given by
e= 1/2 c v²
e= energy stored
c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f
v= potential difference=36 v
so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²
energy stored= 9.72 x 10⁻⁴j
I not completely sure but I hope this helped you
explanation:
the energy stored in the capacitor is given by
e= 1/2 c v²
e= energy stored
c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f
v= potential difference=36 v
so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²
energy stored= 9.72 x 10⁻⁴j
I not completely sure but I hope this helped you
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