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Sagot :
Answer:
T₂ = 1.2 s
Step-by-step explanation:
The time period of a simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{L}{g}}[/tex]
Where
L is length of the pendulum
g is acceleration due to gravity
We have,
T₁ = 1.4 s, L₁ = 0.49 m, L₂ = 0.36 m, T₂= ?
[tex]\dfrac{T_1}{T_2}=\sqrt{\dfrac{L_1}{L_2}} \\\\T_2=\dfrac{T_1}{\sqrt{\dfrac{L_1}{L_2}}}\\\\T_2=\dfrac{1.4}{\sqrt{\dfrac{0.49}{0.36}}}\\\\T_2=1.2\ s[/tex]
So, the new time period is equal to 1.2 seconds.
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