Answer:
–253.5 °C
Explanation:
We'll begin by calculating the number of mole in 6 g of CO₂. This can be obtained as follow:
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Mass of CO₂ = 6 g
Mole of CO₂ =.?
Mole = mass / molar mass
Mole of CO₂ = 6 / 44
Mole of CO₂ = 0.136 mole
Next, we shall convert 225 mL to L.
1000 mL = 1 L
Therefore,
225 mL = 225 mL × 1 L / 1000
225 mL = 0.225 L
Next, we shall determine the temperature of the gas. This can be obtained as follow:
Pressure (P) = 0.855 atm
Volume (V) = 0.225 L
Number of mole (n) = 0.136 mole
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =?
PV =nRT
0.855 × 0.255 = 0.136 × 0.0821 × T
0.218025 = 0.0111656 × T
Divide both side by 0.0111656
T = 0.218025 / 0.0111656
T = 19.5 K
Finally, we shall convert 19.5 K to degree celsius (°C). This can be obtained as follow:
T(°C) = T(K) – 273
T(K) = 19.5 K
T(°C) = 19.5 – 273
T(°C) = –253.5 °C
Therefore, the temperature of the gas is –253.5 °C
