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A system releases 7.9kj of heat while 6.5kj work is done on it. Calculate

Sagot :

stigawithfun

Question:

A system releases 7.9kj of heat while 6.5kj work is done on it. Calculate the total change in internal energy during these operations in kJ.

Answer:

14.4kJ

Explanation:

The first law of thermodynamics which states that the total change in internal energy (ΔU) of a system is the sum of the total heat (Q) released by the system to its surroundings and the total work done (W) on the system by its surrounding, can be expressed mathematically as follows:

ΔU = Q + W      -------------------(i)

From the question;

Q = 7.9kJ

W = 6.5kJ

Substitute these values into equation(i) as follows;

ΔU = 7.9kJ + 6.5kJ

ΔU = 14.4kJ

Therefore, the change in internal energy is 14.4kJ

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