Answered

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225.0 mL of air is at 23.0°C. What is the volume at 90.0 °C?

Sagot :

samueladesida43

Answer:

276 mL

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (mL)

V2 = final volume (mL)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 225mL

V2 = ?

T1 = 23°C = 23 + 273 = 296K

T2 = 90°C = 90 + 273 = 363K

Using V1/T1 = V2/T2

225/296 = V2/363

Cross multiply

296 × V2 = 363 × 225

296V2 = 81675

V2 = 81675/296

V2 = 275.9

V2 = 276 mL

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