Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

What is the equation in stope intercepe form of the line that passes through the points (-4.47) and (2.-16)​

What Is The Equation In Stope Intercepe Form Of The Line That Passes Through The Points 447 And 216 class=

Sagot :

Answer:

[tex]y = -\frac{21}{2}x+5[/tex]

Step-by-step explanation:

Given

[tex](x_1,y_1) = (-4,47)[/tex]

[tex](x_2,y_2) = (2,-16)[/tex]

Required

The equation in slope intercept

First, calculate the slope (m)

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where:

[tex](x_1,y_1) = (-4,47)[/tex]

[tex](x_2,y_2) = (2,-16)[/tex]

So:

[tex]m = \frac{-16 - 47}{2 - -4}[/tex]

[tex]m = \frac{-63}{6}[/tex]

Simplify

[tex]m = -\frac{21}{2}[/tex]

So, the equation is calculated as:

[tex]y = m(x - x_1) + y_2[/tex]

This gives:

[tex]y = -\frac{21}{2}(x - -4) + 47[/tex]

[tex]y = -\frac{21}{2}(x+4) + 47[/tex]

Open bracket

[tex]y = -\frac{21}{2}x-42 + 47[/tex]

[tex]y = -\frac{21}{2}x+5[/tex]