Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
0.703g Na must reacted
Explanation:
The reaction of Sodium, Na, With water, H₂O is:
2Na(s) + 2H₂O(l) → 2NaOH(aq) + H₂(g)
Where 2 moles of sodium reacts with an excess of water to produce 1 mole of hydrogen
To solve this question we have to use PV = nTR to solve the moles of the gas. With the moles of hydrogen we can find the moles of sodium that reacted and its mass:
Moles H₂:
PV = nRT
PV /RT = n
Where P is pressure = 1.15atm
V is volume in liters = 0.325L
R is gas constant = 0.082atmL/molK
T is absolute temperature = 25°C + 273 = 298.0K
1.15atm*0.325L / 0.082atmL/molK*298.0K = n
0.0153 moles of hydrogen are produced
Moles Na:
0.0153 moles H₂ * (2moles Na / 1mol H₂) = 0.0306 moles Na
Mass Na -Molar mass: 22.99g/mol-:
0.0306 moles Na * (22.99g / mol) =
0.703g Na must reacted
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.