mendezmontse0560
Answered

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Calculate the pH of the solution:
[OH-] = 1x10^-11M
a.11.0
b.12.0
c.2.7
d.3.0

Sagot :

iknowThetruth

p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

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