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Answered

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state the type of enthalpy in the followinv equation Koh+Hcl-kcl+h2o ∆h+=-57kj\mol​

Sagot :

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Answer:

The Enthalpy of neutralization

Explanation:

The reaction of a base (KOH) with an acid (HCl) produce water and its salt (KCl) is called Neutralization Reaction.

This neutralization releases 57kJ/mol.

As the type of enthalpy is due the type of reaction. This enthalpy is:

The Enthalpy of neutralization

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