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How do I solve this?

How Do I Solve This class=

Sagot :

14.87

Step-by-step explanation:

use the Pythagorean theorem

a^2+b^2=c^2

C being the longest side of the triangle

14^2+5^2=C^2

196+25=C^2

221=C^

find the square root of 221

C=14.866

rounded to nearest tenth

C=14.87

Answer:

15

Step-by-step explanation:

5^2 +14^2=C^2

25+196=C^2

221=C^2

√221=√C^2

14.86=C

appr 15 =C