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From the roof of a house the angle of depression of
the top of a tree 20 ft. high was found to be 30°. If
the distance between the house and the tree is
10√2 find the height of the house.​


Sagot :

Answer:

GB = CD = 20 ft, GC = BD = 10√3 ft, ∠FAC = 30°, AB = ? Or, AG = 10 ft. hence, the height of the house (AB) = 30 feet is the required answer.

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