Answered

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three consecutive semi
-primes between 30 and 40 are

Sagot :

gauthamsbv9

Answer:

2x = 80. On dividing both sides by 2, we obtain. x = 40. x + 15 = 40 + 15 = 55. Hence ... Let the three consecutive multiples of 8 be 8x, 8(x + 1), 8(x + 2). Sum of ... Number after interchanging = 10 × 3x + x = 30x + x = 31x.

Answer:

33, 34, 35

Step-by-step explanation:

Semiprimes are the product of 2 prime numbers, then

11 × 3 = 33

17 × 2 = 34

7 × 5 = 35

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