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Sagot :
Answer:
Step-by-step explanation:
Check for continuity by evaluating 2^x and -x^2 - 4x + 1 at the break point x = 0: 2^0 is 1 and -x^2 - 4x + 1 is also 1, so these two functions approach the same value as x approaches 0.
Now do the same thing with
-x^2 - 4x + 1 and (1/2)x + 3 at x = 2; the first comes out to -11 and the second to 4. Thus, this function is not continuous at x = 2.
We must reject statement A.
Statement B: as x increases without bound, (1/2)x + 3 also increases without bound. This statement is true.
Statement C: False, because the quadratic -x^2 - 4x + 1 has a maximum at
x = -b/[2a], or x = -(-4)/[-2], or x = -2
Statement D: True: there are no limitations on the values of the input, x.
The statement B is as x approaches positive infinity f(x) approaches positive infinity is true
What is the definition of the limit?
A point or level beyond which something does not or may not extend or pass.
We have to check for continuity by evaluating [tex]2^x[/tex] and [tex]-x^2 - 4x + 1[/tex]
at the break point x = 0
[tex]2^0[/tex]is 1 and [tex]-x^2 - 4x + 1[/tex] is also 1,
So these two functions approach the same value as x approaches 0.
Now do the same thing with
[tex]-x^2 - 4x + 1[/tex]and [tex](1/2)x + 3[/tex] at x = 2;
The first comes out to -11 and the second to 4.
Thus, this function is not continuous at x = 2.
We must reject statement A.
for B we have as x increases without bound,
[tex](1/2)x + 3[/tex]
also increases without bound.
Therefore the statement B is true statement.
Statement C is False,
because the quadratic[tex]-x^2 - 4x + 1[/tex] has a maximum at
[tex]x = -b/[2a],[/tex]
[tex]x = -(-4)/[-2],[/tex]
[tex]x=-2[/tex]
There are no limitations on the values of the input, x.
D is also false negative number are in real numbers.
Therefore,the statement B is as x approaches positive infinity f(x) approaches positive infinity is true
To learn more about the limit visit:
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