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I would like help on this math problem please!

I Would Like Help On This Math Problem Please class=

Sagot :

Answer:

4^11

Step-by-step explanation:

[(4^3)(4^4)]÷(4^1+4^-4)

using laws of indices

(4^3)(4^4)=4^(3+4)

=4^7

(4^1 +4^-4)=4^(1-4)

=4^-3

4^7/4^-3,recalling about laws of indices if the exponentials are dividiy ,you subtract the powers give their base is equal

4^7/4^-3=4^(7-(-3)

=4^(7+3)

=4^11