subikaacharya
Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

sin^2A-cos^2B=sin2^B-cos^2A​

Sagot :

Answer:

see explanation

Step-by-step explanation:

Using the trig identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x

cos²x = 1 - sin²x

Consider the left side

sin²A - cos²B

= (1 - cos²A) - (1 - sin²B) ← distribute parenthesis

= 1 - cos²A - 1 + sin²B

= sin²B - cos²A

= right side , thus verified

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.