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What is the equation of a line that goes through (2,5) and (-2, 3)?​

Sagot :

Answer:

y = 1/2x+4

Step-by-step explanation:

First find the slope

m= (y2-y1)/(x2-x1)

   = (3 - 5)/(-2 -2)

    = -2/-4

   = 1/2

Using point slope form

y -y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-5 = 1/2(x-2)

Distribute

y-5 = 1/2x -1

Add 5 to each side

y-5+5 = 1/2x -1+5

y = 1/2x+4