connerblck420
Answered

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Select the correct answer. What are the solutions of this quadratic equation?

6x^2 + 6 = 12x + 18

[tex]x = 1 + \sqrt{3} [/tex]
[tex]x = 2 + 2 \sqrt[]{3} [/tex]
[tex]x = 2 + \sqrt{6} [/tex]
[tex]x = - 1 \: and \: x = 3[/tex]


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Sagot :

thezekromninja

Answer:

x=1+√3

Step-by-step explanation:

Let's solve your equation step-by-step.

6x^2+6=12x+18

Step 1: Subtract 12x+18 from both sides.

6x^2+6−(12x+18)=12x+18−(12x+18)

6x^2−12x−12=0

For this equation: a=6, b=-12, c=-12

6x^2+−12x+−12=0

Step 2: Use quadratic formula with a=6, b=-12, c=-12.

x=−b±√b2−4ac/2a

x=−(−12)±√(−12)2−4(6)(−12)/2(6)

x=12±√432/12

x=1+√3

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