Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Use the quadratic formula to solve for x.
6x²-3x=1
Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.


Sagot :

If we know the quadratic formula, the quadratic formula is

x = [-b ± √(b²- 4ac)] / 2a

Gosh! So overwhelming! But let's look at the composition of a quadratic equation:

ax² + bx + c = 0

And we have 6x² - 3x = 1. So, what do we do? We need to put this quadratic equation into an easy form to find the value of a, b, and c to plug in to the equation.

We can just minus one on both sides to get this:

6x² - 3x - 1 = 0

Is it in the form of ax² + bx + c? Yes! a = 6, b = -3, and c = -1. Now, all we have to do is plug it into the quadratic formula.

x = [-b ± √(b²- 4ac)] / 2a

x = [-(-3) ± √((-3)²- 4(6)(-1))] / 2(6)

     [3 ± √(9- 4(6)(-1))] / 12

     [3 ± √(9 + 24)] / 12

     [3 ± √(33)] / 12

At this point, we should just use a calculator, and recognize we have two answers because of the plus-or-minus sign! (or this sign: ±)

[3 ± √(33)] / 12

1) [3 + √(33)] / 12 = 0.73 approximately

2) [3 - √(33)] / 12 = -0.23 approximately

So, x=0.73 and x= -0.23.