Answered

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Given P(A) = 0.74, P(B) = 0.6 and P(ANB) = 0.494, find the value of
P(AB), rounding to the nearest thousandth, if necessary.

Sagot :

mbleeed

Step-by-step explanation: Since we have given, P(A) = 0.75 and P(A|B) =0.8 .

So, P(A∩B) = P(B|A)× P(A) = 0.8×0.75 =0.6 .

We have given P(B|A') = 0.6

P(A’∩B) = P(B|A')×P(A') = 0.6 × 0.25 = 0.15.

P(B) = P(A∩B) + P(A'∩B) = 0.6 + 0.15 = 0.75.

=> P(A|B) = (∩)()=0.60.75

P

(

A

∩

B

)

P

(

B

)

=

0.6

0.75

= 0.8 .

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