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answer all questions 9-13!!!!​

Answer All Questions 913 class=

Sagot :

Answer:

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

Step-by-step explanation:

9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in

10) 3×4 (the quadrilateral at the bottom)

11)∵ A= Cross-sectional area× height

  ⇒A= Area of the trapezium × 4

  ∴ A=[tex]\frac{1}{2} \\[/tex] (sum of the parallel sides) × 4

  A=[tex]\frac{1}{2} \\[/tex] (3+6) × 4

  A= 18 in²

12) V=πr²h

    V=π(6)²(12)

⇒V=432 cm³

   TSA=2(πr²)+2πrh

  TSA=2(π(6)²)+2π(6)(12)

 ⇒TSA=240π cm²

13. V=πr²h

    V=π(8)²(7)

   V=448π ft³

TSA=2(πr²)+2πrh

TSA=2(π(8)²)+2π(8)(7)

TSA=240π ft²

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

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