At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

answer all questions 9-13!!!!​

Answer All Questions 913 class=

Sagot :

Answer:

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

Step-by-step explanation:

9) Since all side of the trapezium are the same the height = perpendicular line which is 3.7 in

10) 3×4 (the quadrilateral at the bottom)

11)∵ A= Cross-sectional area× height

  ⇒A= Area of the trapezium × 4

  ∴ A=[tex]\frac{1}{2} \\[/tex] (sum of the parallel sides) × 4

  A=[tex]\frac{1}{2} \\[/tex] (3+6) × 4

  A= 18 in²

12) V=πr²h

    V=π(6)²(12)

⇒V=432 cm³

   TSA=2(πr²)+2πrh

  TSA=2(π(6)²)+2π(6)(12)

 ⇒TSA=240π cm²

13. V=πr²h

    V=π(8)²(7)

   V=448π ft³

TSA=2(πr²)+2πrh

TSA=2(π(8)²)+2π(8)(7)

TSA=240π ft²

9)  3.7 in

10) 12 in²

11) 18 in³

12) V=432π cm³

   TSA= 216π cm²

13)V=448π ft³

   TSA=240π ft²

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.