Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
The amount to remove from each corner is a square, 4/3 ft by 4/3 ft.
Step-by-step explanation:
The piece of cardboard measures 8 ft by 8 ft.
Each corner will be cut to create the sides of the box.
Let the square cut from each corner measure x by x ft.
The base of the box will measure 8 - 2x by 8 - 2x, and the height of the box will be x.
V = (8 - 2x)^2 * x
V = 64x - 32x^2 + 4x^3
Now we differentiate and set the derivative equal to zero to find a maximum value.
64 - 64x + 12x^2 = 0
3x^2 - 16x + 16 = 0
(3x - 4)(x - 4) = 0
3x - 4 = 0 or x - 4 = 0
3x = 4 or x = 4
x = 4/3 or x = 4
The solution x = 4 must be discarded since 8 - 2x = 8 - 8 = 0, and the sides would have 0 length.
The amount to remove from each corner is a square, 4/3 ft by 4/3 ft.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.