Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

how much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?

Sagot :

Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Explanation:

Given: Mass = 20 g

Change in temperature = [tex]26^{o}C[/tex]

The standard value of specific heat of water is [tex]4.184 J/ g^{o}C[/tex]

Formula used to calculate the heat energy is as follows.

[tex]q = m \times C \times \Delta T[/tex]

where,

q = heat energy

m = mass of substance

C = specific heat of substance

[tex]\Delta T[/tex] = change in temperature

Substitute the values into above formula as follows.

[tex]q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J[/tex]

Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.