LyricallyDamaged
Answered

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PLZ HELP!!! I'm begging you! Problem: If each letter of the alphabet is worth two more numbers than the number before it (1=1, 2=3), what is the entire alphabet worth?

Sagot :

mj3mar

Answer:

676

Step-by-step explanation:

I think this is an arithmetic series, so

Sn = 26/2[2(1) + (26 - 1)2]

Sn = 13[2 + 50]

Sn = 13[52]

Sn = 676

mathstudent55

Answer:

676

Step-by-step explanation:

A = 1

B = 3

C = 5

D = 7

...

Z = 51

              1   + 3    + 5   + 7    + 9 + 11  + 13  + 15  + 17  + 19 + 21 + 23 + 25

(+)       + 51 + 49 + 47 + 45 + 43 + 41 + 39 + 37 + 35 + 33 + 31 + 29 + 27

---------------------------------------------------------------------------------------------------

          52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52

13 * 52 = 676

Answer: 676

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