Answer:
433 m²
Step-by-step explanation:
Find the side length of the square first.
Apply Pythagoras Theorem on 1 of the triangles on the right, to find its remaining side.
[tex] \sqrt{ {12}^{2} - {9.6}^{2} } [/tex]
=[tex] \sqrt{51.84} [/tex]
= 7.2 m
Therefore the side of the square is
7.2 ×2
= 14.4 m
The area of the square
= 14.4²
= 207.36 m²
You are able to find the area if of the 2 triangles.
(7.2 × 9.6)÷2 ×2
= 69.12 m²
The height of the pentagon
= 25.4 - 7.2
= 18.2 m
The area of the pentagon
= (10+7.2) × 18.2 ÷ 2
= 156.52 m²
Add up the areas of the 3 polygons.
The area of the shape
= 207.36 + 69.12 + 156.52
= 433 m²
