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CAN SOMEONE HELP ME PLEASE

CAN SOMEONE HELP ME PLEASE class=

Sagot :

The solution is acute angles
breadsticksandcheese

Answer:

x = 4, y = -3

Step-by-step explanation:

Find the slope intercept form first (y = mx + b):

the one going down is y = -1/2x - 1 (slope is negative, down 1 over 2, and the y-intercept is at (0, -1) )

the one going up is y = 1/4x - 4 (slope is up 1 over 4, and the y-intercept is at (0, -4)

Convert them into standard form (Ax + By = C):

1st equation: multiply the entirety of both sides by 2 to get rid of the fraction:

2y = -1x -`2

add 1x to both sides: 1x + 2y = -2

2nd equation: multiply the entirety of both sides by 4 to get rid of the fraction:

4y = 1x - 16

subtract 1x from both sides: -1x + 4y = -16

Isolate a variable:

-x + 4y = -16

-x = -4y - 16

x = 4y + 16

Plug that into other equation:

1(4y + 16) + 2y = -2

6y + 16 = -2

6y = -18

y = -3

Substitute y into the isolated equation:

x = 4(-3) + 16

x = -12 + 16

x = 4

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