At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

3. A circle with center (0,0) has a y-intercept at (3,0).
Find the equation of the circle.


Sagot :

Answer:

x^2 + y^2 = 9

Step-by-step explanation:

The standard equation of a circle with center at (h, k) and radius r is

(x - h)^2 + (y - k)^2 = r^2.  Here h = 0, k = 0, x = 3 and y = 0:

(3 - 0)^2 + (0 - 0)^2 = r^2, or

9 = r^2.  Thus, the radius is 3.

The equation of this circle is (x - 0)^2 + (y - 0)^2 = 9, or

x^2 + y^2 = 9