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Please help!! giving a lot of points
A rollercoaster cart that has a mass of 4500 kg has 67.5 kJ (kilojoules), or 67,500 J (joules), of gravitational potential
energy. What is its height above the ground?


PT.2

The same 4500 kg rollercoaster cart is moving with 63.0 kJ (kilojoules), or 63,000 J (joules), of kinetic energy at the


bottom of its biggest hill. What is its velocity?

Sagot :

Question 1.

  • mass = 4500 kg
  • potential energy (p.e) = 67500 J

now, we know :

=》

[tex]p.e = mgh[/tex]

=》

[tex]67500 = 4500 \times 10 \times h[/tex]

=》

[tex]67500 = 45000 \times h[/tex]

=》

[tex]h = \dfrac{67500}{45000} [/tex]

=》

[tex]h = 1.5 \: m[/tex]

note : if we take acceleration due to gravity as 9.8, then height = 1.53 m

Question 2.

  • mass = 4500 kg
  • kinetic energy = 63000 j

we know,

=》

[tex]k.e = \dfrac{1}{2} mv {}^{2} [/tex]

=》

[tex]63000 = \dfrac{1}{2} \times 4500 \times {v}^{2} [/tex]

=》

[tex] {v}^{2} = \dfrac{63000 \times 2}{4500} [/tex]

=》

[tex] {v}^{2} = 28[/tex]

=》

[tex]v = \sqrt{28} [/tex]

=》

[tex]v = 2 \sqrt{7} \: \: ms {}^{ - 1} [/tex]

or

=》

[tex]5.29 \: \: ms {}^{ - 1} [/tex]

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