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find the distance of line segment AB between the points at (8,0) and (5,9)

Sagot :

SajjadGedow

Answer:

Approximately 3.605 units

Step-by-step explanation:

AB= B -A = [tex]\left[\begin{array}{ccc}5\\9\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}8\\0\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}-3\\9\end{array}\right][/tex]

|AB| = √x²+y² = √(-3)²+2² = √9+4 =√13 = 3.605 units

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