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Sagot :
Here's the solution,
volume :
=》
[tex] \dfrac{1}{2} \times 12 \times 5 \times 3[/tex]
=》
[tex]90 \: \: m {}^{3} [/tex]
surface area :
=》
[tex](13 \times 3) + (5 \times 3) + (12 \times 3) + (2 \times \dfrac{1}{2} \times 12 \times 5)[/tex]
=》
[tex]39 + 15 + 36 + 60[/tex]
=》
[tex]150 \: \: {m}^{2} [/tex]
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