Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

1.
A rock is thrown upward with a velocity of 12 meters per second from the top of a 28
meter high cliff, and it misses the cliff on the way back down. When will the rock be 5
meters from ground level? Round your answer to two decimal places.
Gravity Formula


PLS HELP

Sagot :

Answer:

The rock will be be 5  meters from ground level at time = 3.713 seconds

Step-by-step explanation:

As we know-

[tex]s(t) = -4.9 * t^2 + v_0t + s_0[/tex]

V0 = velocity

S0 = height above ground when thrown

Substituting the given values, we get -  

[tex]9 = -4.9* t^2 + 12 * t +32\\-4.9*t^2 +12*t + 23 = 0[/tex]

As per the formula

[tex]t = \frac{-12+ \sqrt{12^2 -4*(-4.9)*23} }{(2*(-4.9)} \\t = 3.713[/tex]

The rock will be be 5  meters from ground level at time = 3.713 seconds