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According to the balanced chemical equation below, how many grams of CO2 would be produced
from 20 grams of C3H18 and excess O2?
2 C3H18 + 25 O2 --> 16 CO2 + 18 H20

Sagot :

dsdrajlin

Answer:

62 g

Explanation:

Step 1: Write the balanced combustion equation

2 C₈H₁₈ + 25 O₂ ⇒ 16 CO₂ + 18 H₂O

Step 2: Calculate the moles corresponding to 20 g of C₈H₁₈

The molar mass of C₈H₁₈ is 114.23 g/mol.

20 g × 1 mol/114.23 g = 0.18 mol

Step 3: Calculate the moles of CO₂ produced from 0.18 moles of C₈H₁₈

The molar ratio of C₈H₁₈ to CO₂ is 2:16. The moles of CO₂ produced are 16/2 × 0.18 mol = 1.4 mol

Step 4: Calculate the mass corresponding to 1.4 moles of CO₂

The molar mass of CO₂ is 44.01 g/mol.

1.4 mol × 44.01 g/mol = 62 g

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