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What volume will 2.0 moles of nitrogen occupy at 0.947 atm and 20.0 °C?


Sagot :

Answer:

V = 50.77 L

Explanation:

Given that,

No. of moles, n = 2

Pressure, P = 0.947 atm

Temperature, T = 20°C = 293 K

We need to find the volume occupies by Nitrogen gas. Using gas law,

[tex]PV=nRT\\\\V=\dfrac{nRT}{P}[/tex]

Where

R is gas constant

Put all the values,

[tex]V=\dfrac{2\times 0.08205\times 293}{0.947}\\\\V=50.77\ L[/tex]

So, the volume occupied by the gas is equal to 50.77 L.