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PLEASE HELP ME IM STUCKKKKK

PLEASE HELP ME IM STUCKKKKK class=

Sagot :

Answer:

[tex]x=\sqrt{10}[/tex]

Step-by-step explanation:

For first right angled tringle,

Hypotenuse = 10

Height = 9

We can find the base of first triangle using Pythagoras therorem,

[tex]b=\sqrt{10^2-9^2}\\\\=\sqrt{100-81}\\\\=\sqrt{19}[/tex]

Now, for other triangle,

Height = 3

Hypotenuse = [tex]\sqrt{19}[/tex]

So,

[tex]x=\sqrt{(\sqrt{19})^2-3^2}\\\\=\sqrt{19-9}\\\\=\sqrt{10}[/tex]

So, the value of x is equal to [tex]\sqrt{10}[/tex].

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