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How many grams of ethanol, C2H5OH, can be boiled with 843.2 kJ of heat energy? The molar heat of vaporization of ethanol is 38.6 kJ/mol.

Sagot :

dsdrajlin

Answer:

1.00 × 10³ g

Explanation:

Step 1: Given data

  • Provided heat (Q): 843.2 kJ
  • Molar heat of vaporization of ethanol (ΔH°vap): 38.6 kJ/mol

Step 2: Calculate the moles of ethanol vaporized

Vaporization is the passage of a substance from liquid to gas. We can calculate the number of moles (n) vaporized using the following expression.

Q = ΔH°vap × n

n = Q / ΔH°vap

n = 843.2 kJ / (38.6 kJ/mol) = 21.8 mol

Step 3: Calculate the mass corresponding to 21.8 moles of ethanol

The molar mass of ethanol is 46.07 g/mol.

21.8 mol × 46.07 g/mol = 1.00 × 10³ g

The conversion of the liquid into water vapor is called vaporization.

The correct answer to the question is [tex]1.00 * 10^3 g[/tex]

The data given in the question is as follows:-

  • Provided heat (Q): 843.2 kJ
  • Molar heat of vaporization of ethanol (ΔH°vap): 38.6 kJ/mol

The formula we will use to calculate the moles is as:-

[tex]Q = H^ovap* n\\n = \frac{Q}{H^ovap}\\n = \frac{843.2 kJ}{(38.6 kJ/mol)} \\\\= 21.8 mol[/tex]

To calculate the mass of the following is as follows:-

  • The molar mass of ethanol is 46.07 g/mol.

[tex]21.8 mol* 46.07 g/mol = 1.00 * 10^3 g[/tex]

Hence the correct answer is [tex]1.00 * 10^3 g[/tex].

For more information, refer to the link:-

https://brainly.com/question/22810476

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