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How many permutations of a 7-digit phone number exist if any number 0-9 may be used but repetition is not allowed?

Sagot :

Answer:

There are 604,800 possible permutations.

Step-by-step explanation:

The order in which the digits are chosen is important, which means that the permutations formula is used to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this question:

7 digits from a set of 10(10 digits to 0-9). So

[tex]P_{(10,7)} = \frac{10!}{(10-7)!} = 604800[/tex]

There are 604,800 possible permutations.

medinaisabella52

Answer:

10!/3!

Step-by-step explanation:

i just took a test and got it right

Because repetition is not allowed, and there are 10 initial options for the 7 decisions that need to be made, we use the formula

n!/(n-r)! = 10!/(10-7)! = 10!/3!

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