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Sagot :
Step-by-step explanation:
Question:-
[tex]\\ \tt{:}\leadsto 5(x+2)=30[/tex]
SOLUTION:-
[tex]\\ \tt{:}\leadsto 5(x+2)=30[/tex]
[tex]\\ \tt{:}\leadsto 5x+10=30[/tex]
[tex]\\ \tt{:}\leadsto 5x=30-10[/tex]
[tex]\\ \tt{:}\leadsto 5x=20[/tex]
[tex]\\ \tt{:}\leadsto x=\dfrac{20}{5}[/tex]
[tex]\\ \tt{:}\leadsto x=4[/tex]
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\textsf{5(x + 2) = 30}\\\large\textsf{5(x) + 5(2) = 30}\\\large\textsf{5x + 10 = 30}\\\large\text{SUBTRACT 10 to BOTH SIDES}\\\large\textsf{5x + 10 - 10 = 30 - 10}\\\large\text{CANCEL out: 10 - 10 because it gives you 0}\\\large\text{KEEP: 30 - 10 because it helps you solve for your x-value}\\\large\text{NEW EQUATION: \textsf{5x = 30 - 10}}\\\large\text{SIMPLIFY IT}\uparrow\\\large\textsf{5x = 20}\\\large\text{DIVIDE 5 to BOTH SIDES}\\\mathsf{\dfrac{5x}{5} = \dfrac{20}{5}}[/tex]
[tex]\large\text{CANCEL out: }\rm{\dfrac{5}{5}}\large\text{ because it gives you 1}\\\large\text{KEEP: }\rm{\dfrac{20}{5}}\large\text{ because it gives you the result of the x-value}\\\text{NEW EQUATION: x = }\rm{\dfrac{20}{5}}\\\large\text{x = 20\ }\div\large\text{ 5}\\\large\text{SIMPLIFYIT!}\uparrow\\\large\textsf{x = 4}\\\huge\boxed{\textsf{Therefore, your answe is: x = 4}}\huge\checkmark\\\\\\\\\\\huge\text{Good luck on your assignment \& enjoy your day!}\\\\\\\\\frak{Amphitrite1040:)}[/tex]
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