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Find the molarity of 4.18 g MgCI2 in 500mL of water

Sagot :

whitneytr12

Answer:

The molarity of MgCl₂ in water is 0.088 mol/L.

Explanation:

The molarity of MgCl₂ can be calculated as follows:

[tex] C = \frac{\eta}{V} = \frac{m}{MV} [/tex]

Where:

C: is the molarity =?

η: is the number of moles of MgCl₂ = m/M

V: is the volume of water = 500 mL = 0.500 L

m: is the mass of MgCl₂ = 4.18 g

M: is the molar mass of MgCl₂ = 95.211 g/mol

Hence, the molarity is:

[tex] C = \frac{m}{MV} = \frac{4.18 g}{95.211 g/mol*0.500 L} = 0.088 mol/L [/tex]

Therefore, the molarity of MgCl₂ in water is 0.088 mol/L.

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